Question

For the following reaction 2BrCl(g) ? Br2(g) + Cl2(g) Kc = 32 at 500 K. At equilibrium, the concentration of Br2 is 0.22 M and of Cl2 is 0.015 M. Calculate the equilibrium concentration of BrCl. A. 0.0064 M B. 0.0033 M C. 0.21 M D. 0.00010 M E. 0.010 M

          For the following reaction

2BrCl(g) ? Br2(g) + Cl2(g)

Kc = 32 at 500 K. At equilibrium, the concentration of Br2 is 0.22 M and of Cl2 is 0.015 M. Calculate the equilibrium concentration of BrCl.

A. 0.0064 M B. 0.0033 M C. 0.21 M D. 0.00010 M E. 0.010 M

For the following reaction

2BrCl(g) ? Br2(g) + Cl2(g)

Kc = 32 at 500 K. At equilibrium, the concentration of Br2 is 0.22 M and of Cl2 is 0.015 M. Calculate the equilibrium concentration of BrCl.

A. 0.0064 M B. 0.0033 M C. 0.21 M D. 0.00010 M E. 0.010 M

Added by Yolanda L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Preeti Kumari

06/09/2022

Step 1

22 M - [Cl2] = 0.015 M Show more…

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For the following reaction: 2BrCl(g) ⇌ Br2(g) + Cl2(g) Kc = 32 at 500 K. At equilibrium, the concentration of Br2 is 0.22 M and the concentration of Cl2 is 0.015 M. Calculate the equilibrium concentration of BrCl. A. 0.0064 M B. 0.0033 M C. 0.21 M D. 0.00010 M E. 0.010 M