4) For the following reaction; C(s) + H2O(g) = CO(g) +...

4) For the following reaction; C(s) + H2O(g) = CO(g) + H2(g) Calculate the enthalpy of reaction using the reaction provided. 2 C(s) + 2 O2(g) = 2 CO2(g) H = -188 kJ CO(g) + 1/2 O2(g) = CO2(g) H = -67.6 kJ 4 H2(g) + 2 O2(g) = 4 H2O(g) H = -230.2 kJ 31.15 kJ -104.05 kJ - 83.95 kJ 219.15 kJ

Transcript

00:01 All right, so we have a reaction here, for the reaction between carbon and water to give you carbon monoxide and hydrogen gas and we're asked to calculate the delta h of this reaction given all of this.

00:19 So we're going to be using hess's law here and what will happen is we're going to take each equation given, look at its components and see.

00:29 If you look at our reaction, carbon, we have one mole of carbon on the reactant side.

00:36 The equation we have provided that has carbon, we have two moles of carbon.

00:40 So we're going to have to change or rewrite that equation so that we would have divided the entire equation by two so that we have this and also the delta h will be divided by two so the new delta h for that reaction would definitely be 188 divided by two and that's minus 94.

01:05 So that's the first one.

01:07 Let's call that delta h1.

01:10 The equation, the delta h, we don't know.

01:13 Let's we're going to call that just delta h.

01:16 Okay, let's look at the next one, water.

01:18 The equation that has water is this one, is this last equation, right? and you have one mole of water here.

01:25 Here we have four and the water that we have is on the reactant side, is on the product side in this equation but in our equation we want it on the reactant.

01:35 So we're going to flip this equation.

01:37 We're going to rewrite that one so that it becomes and divide it by four, the entire equation by four.

01:43 So water will decompose, would have hydrogen gas plus, you know, two moles of hydrogen gas but divided by four, sorry, so hydrogen plus half mole of oxygen gas and where the delta h will change sign, i'm going to call that delta h2...

Question

4) For the following reaction; C(s) + H2O(g) = CO(g) + H2(g) Calculate the enthalpy of reaction using the reaction provided. 2 C(s) + 2 O2(g) = 2 CO2(g) H = -188 kJ CO(g) + 1/2 O2(g) = CO2(g) H = -67.6 kJ 4 H2(g) + 2 O2(g) = 4 H2O(g) H = -230.2 kJ 31.15 kJ -104.05 kJ - 83.95 kJ 219.15 kJ

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