00:01
Hello students, in this question we have to distinguish the following compounds into r2 chlorobutane and s2 chlorobutane.
00:09
This is the first compound given in the question.
00:11
We are going to give the periodicity for this compound.
00:14
The halide group will deserve the first periodicity and the second one is the ethyl group and the third one is the methyl group and fourth one least periodicity is the hydrogen group.
00:25
This shows an anti -clockwise rotation and moreover the less periodicity group that is hydrogen lies above the plane.
00:36
Therefore, it will result in the reverse of the optical activity that is s conformer will be converted to r.
00:44
Therefore, the product is r2 chlorobutane.
00:52
Coming to the second product, this is our second product and there is a methyl group lies below the plane and there must be a hydrogen that lies above the plane.
01:04
Now we are going to give the periodicity.
01:07
The chlorine will have the first and followed by ethyl and methyl and the last one is the hydrogen...