00:01
Hello guys, let's get started with the solution.
00:06
When we talk about bronzed acids, bronzed base, and strongest base to h plus and strongest base to bme3.
00:41
So at first, bronzed acids are the ones which gives h plus signs in the solution.
00:51
So, we know that metal hydride which have greater electronegativity difference would give the essence in the solution and in a period electronegativity decreases from left to right therefore te being more electronegative has the highest acidic character then comes sbh3 and after that is s and h4 based on electronegatively when we come to bronchstead basis then we know that dronsted basis are the ones which accepts h plus ions.
01:44
So among the givens, n .h3, ph3 and sbs3, we know that nitrosin has the loan curves easily available due to the high electronegativity here and the most basic nature.
02:02
Therefore it would be most basic here while the sbah3 would be the least basic here.
02:12
Now when it comes to the strongest base 2 s plus then we are provided with ns 3, cs3 n h 2, cs3 whole twice n h and c s 3 whole twice and here.
02:31
We know that more easily the loan pairs available, more strongest is the base 2 s plus here.
02:41
So at this point 3 degrees should be the most basic here but due to steric hindrance of the three methyl groups here 2 degree is the most basic then comes the primary one at second position then comes tertiary at third position and at last with the ammonia here now when it comes to the strongest base to bm3 then bm3 here has boron which is electron deficient here therefore the one which can easily donate its loan credits towards bm a three would be the strongest base.
03:19
Now for bma3 were provided with pyridine.
03:28
The next one is 4 methyl pyridine.
03:44
While the other one is 2 methyl pyedine.
03:52
We know that methyl substituent has the ability...