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For the following system of equations, enter the solution in the blanks below, or if there is no solution, enter dne for each blank. $x + 0y - 4z = 1$ $2x - y - 6z = 4$ $2x + 3y - 2z = 8$ Blank #1: x-value of the solution. Enter the value only. Blank #2: y-value of the solution. Enter the value only. Blank #3: z-value of the solution. Enter the value only. Blank # 1 Blank # 2 Blank # 3 

          For the following system of equations, enter the solution in the blanks below, or if there is no solution, enter dne for each blank.
$x + 0y - 4z = 1$
$2x - y - 6z = 4$
$2x + 3y - 2z = 8$
Blank #1: x-value of the solution. Enter the value only.
Blank #2: y-value of the solution. Enter the value only.
Blank #3: z-value of the solution. Enter the value only.
Blank # 1
Blank # 2
Blank # 3
Show more…
For the following system of equations, enter the solution in the blanks below, or if there is no solution, enter dne for each blank. x + 0y - 4z = 1 2x - y - 6z = 4 2x + 3y - 2z = 8 Blank #1: x-value of the solution. Enter the value only. Blank #2: y-value of the solution. Enter the value only. Blank #3: z-value of the solution. Enter the value only. Blank # 1 Blank # 2 Blank # 3

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Introductory and Intermediate Algebra for College Students 4th
Introductory and Intermediate Algebra for College Students 4th
Robert Blitzer 4th Edition
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For the following system of equations, enter the solution in the blanks below, or if there is no solution, enter "dne" for each blank. x + 0y - 4z = 1 2x - y - 6z = 4 2 + 3y - 2z = 8 Blank #1: x-value of the solution. Enter the value only. Blank #2: y-value of the solution. Enter the value only. Blank #3: z-value of the solution. Enter the value only. Blank #1: A Blank #2: A Blank #3: A
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Transcript

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00:01 Here we have to solve the system of equations given by x minus of y plus of 3 z is equals to 8 and the 3x plus of y minus of 2 z is equals to minus of 2 and 2x plus of 4y plus of z is equals to 0.
00:27 Now let's name these equation as equation first, equation second and equation third.
00:34 To solve this system of equations, let's use first two equations and then add them.
00:39 So we will use the operation equation 1 plus of equation 2.
00:45 So we will have x minus of y plus of 3z is equal to 8 and 3x plus of y minus 2z is equal to minus 2 on adding these two equations we will have 4x plus of z is equals to 6 so we can name this equation as equation 4th now next we will use the last two equations and we will use the operation as minus of 4 into equation second plus of equation 3 so we will have this as minus of 12x minus of 4y plus of 8 z is equal to 8 and 2x plus of 4y plus of z is equals to 0...
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