00:01
In this problem, we'll first give in any molecular formula that looks like this, and we're asked to draw two isomers for it.
00:07
So first, let's find degrees on saturation.
00:10
So this will tell us the number of pyvons and the number of rings together.
00:18
So to calculate this, we do the number of carbons times 2 plus 2, subtract the number of hydrogens, and divide by 2.
00:28
So when we do this, we get 5.
00:31
So combined we have five pie bonds and rings.
00:36
So here what comes to mind is a cyclohexane ring.
00:41
So a ring is one degree of unsaturation.
00:44
And we know we have two ketones.
00:47
So if we draw it like this, and part of what should help you think of a ring here is the fact that no carbon will have more than one hydrogen.
00:58
So here we're still missing two degrees of unsaturation...