Question

For the network shown in the given figure, find $v(t)$ for $t > 0$. Assume $L = 1 H$. 5? $t = 0$ 6? 2A 12 ? 20 ? L +20 V The voltage $v(t) = \boxed{\qquad}e^{-t/\boxed{\qquad}}V$ for $t > 0.$

          For the network shown in the given figure, find $v(t)$ for $t > 0$. Assume $L = 1 H$.
5?
$t = 0$
6?
2A
12 ?
20 ?
L
+20 V
The voltage $v(t) = \boxed{\qquad}e^{-t/\boxed{\qquad}}V$ for $t > 0.$

For the network shown in the given figure, find v(t) for t > 0. Assume L = 1 H.
5?
t = 0
6?
2A
12 ?
20 ?
L
+20 V
The voltage v(t) = e^-t/ V for t > 0.

Added by Robert V.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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For the network shown in the given figure, find V for t > 0. Assume L = 1H. 1 = 0 X 6 20V 2A 4 129 20 The voltage = e^(-t/) V for t > 0.

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Question

For the network shown in the given figure, find $v(t)$ for $t > 0$. Assume $L = 1 H$. 5? $t = 0$ 6? 2A 12 ? 20 ? L +20 V The voltage $v(t) = \boxed{\qquad}e^{-t/\boxed{\qquad}}V$ for $t > 0.$

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