00:01
In this question we have given that for the oscilloscope trace we have given the time base for each horizontal division and vertical division then we have to find in the first part the amplitude of the wave.
00:17
So given we have that the horizontal division is one horizontal division is equal to 0 .005 second and one vertical division is equal to 0 .005 second and one vertical division is equals to the 1 world.
00:43
Now, amplitude, as we know that, amplitude is the maximum vertical displacement from center line.
01:03
So from the graph, we can say that, and this is equal to four vertical divisions.
01:14
So the amplitude will be, one vertical division is 1 volt, so the amplitude is 4 volt.
01:19
So this is the amplitude.
01:21
Next, we have to find.
01:23
The peak to peak voltage so peak to peak voltage is calculated as this is the total vertical displacement so we can say that from the graph that is equal to eight vertical divisions and the peak to peak voltage will be eight times of b next we have to find the voltage would you measure with a digital voltimeter on ac scale so that is the vrms voltage is equals to this is amplitude voltage upon root 2.
02:31
So this is 4 by root 2 and that will comes out 2 .82 volts...