Question

For the path shown below $I_2 = 4, 6A$ and you calculate $\oint \vec{B} \cdot d\vec{l} = 1,49 \times 10^{-5} Tm$. Find the magnitude of the current $I_1$. Round your results to two decimal places. ($\mu_0 = 4\pi10^{-7} Tm/A$) closed path $I_2$ $I_1$

Name: for the path shown below i2 4 6a and you calculate oint vecb cdot dvecl 149 times 10 5 tm find the magnitude of the current i1 round your results to two decimal places mu0 4pi10 7 tma clo 09094
Uploaded: 2023-06-06T20:26:49-08:00
Duration: 4 min 11 s
Channel: Aparna Shakti
Description: for the path shown below i2 4 6a and you calculate oint vecb cdot dvecl 149 times 10 5 tm find the magnitude of the current i1 round your results to two decimal places mu0 4pi10 7 tma clo 09094

          For the path shown below $I_2 = 4, 6A$ and you calculate $\oint \vec{B} \cdot d\vec{l} = 1,49 \times 10^{-5} Tm$. Find the magnitude of the current $I_1$. Round your results to two decimal places. ($\mu_0 = 4\pi10^{-7} Tm/A$)
closed path
$I_2$
$I_1$

for the path shown below i2 4 6a and you calculate oint vecb cdot dvecl 149 times 10 5 tm find the magnitude of the current i1 round your results to two decimal places mu0 4pi10 7 tma clo 09094

Added by Nathan E.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aparna Shakti

06/06/2023

Step 1

Ampere's Law states that the line integral of the magnetic field $\vec{B}$ around a closed loop is proportional to the total current $I_{enc}$ passing through the loop: $\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{enc}$ where $\mu_0$ is the permeability of free space. Show more…

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For the path shown below $I_2 = 4, 6A$ and you calculate $\oint \vec{B} \cdot d\vec{l} = 1,49 \times 10^{-5} Tm$. Find the magnitude of the current $I_1$. Round your results to two decimal places. ($\mu_0 = 4\pi10^{-7} Tm/A$) closed path $I_2$ $I_1$