00:01
Hello students, here in this question, a peptide group is given and from this peptide one we have to write a single letter code.
00:08
The given forms are of the three letter code.
00:16
So how we will form the single letter code? we only have to write the first letters and the second single letter code for the peptide.
00:25
Here we can say that for aligning it is a, for 16 it is c, for the histuring it is s, whereas the is a is represented by small letter i, where the lozen is represented by capital l and s -pargeon is represented by n.
00:41
This will be a single -letter code for the given peptide.
00:44
Next we have to find out the charge of the peptide.
00:47
In order to find that first of we have to know that if the ph value is less than pka value we have to give the charge as plus one.
00:55
If the ph value is greater than the pka value we have to give the values minus 1 as here this question they have also provided with the pk a value here we can see that for the al -anine we can take it as 3 the p -k -a value as this p -k -a value of al -a which is represented by capital a which is what less than ph value so here we can be with it as minus 1 4 dot of the system it's given as 4 which is also less than ph we can give it as minus 1 for that of the history it is 6 which is also less than ph value 7 we can give it as minus 1 but as in the case of isolucin it is greater than ph so here we have to give the value of plus 1 for that of the loosen also the pk value is greater than the ph so we have to give the plus 1 so in this way we have to add all the charges that is minus 1 plus minus 1 plus plus 1 plus plus 1.
02:02
In order of this we will get the minus 1.
02:04
So again we can say is that the charge of peptide is equal to minus 1...