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For the piecewise function, find the values g(-7), g(2), and g(9). $g(x) = egin{cases} x + 3, & \text{for } x \le 2 \\ 8 - x, & \text{for } x > 2 \end{cases}$ g(-7) = g(2) = g(9) = 

          For the piecewise function, find the values g(-7), g(2), and g(9).
$g(x) = egin{cases} x + 3, & \text{for } x \le 2 \\ 8 - x, & \text{for } x > 2 \end{cases}$
g(-7) = 

g(2) = 

g(9) =
For the piecewise function, find the values g(-7), g(2), and g(9). g(x) = egincases x + 3, for x ≤ 2 8 - x, for x > 2 g(-7) = g(2) = g(9) =

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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For the piecewise function, find the values g(-7), g(2), and g(9). g(x) = g(-7)= g(2) = g(9) = x + 3, for x ≤ 2 8-x, for x>2 For the piecewise function,find the values g-7,g2,and g9) x+3,forx2 gx= 8-x,forx>2 g-7= g2= =66
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Transcript

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00:01 This problem gives us a piecewise function and wants us to evaluate g of negative 1, g of 4, and g of 5.
00:06 And to do that correctly, we need to look at the piecewises and what intervals our x values lies in for each piece.
00:13 So we have x plus 4 where x is less than equal to 4, and then 7 minus x when x is greater than 4.
00:20 So when we go to choose which part of our piecewise to plug into, we'll analyze our x value and decide which interval does it fall in.
00:27 Negative 1 is less than or equal to 4.
00:29 So for our first evaluation, we'll use x plus nine.
00:32 So negative one for x plus nine means that negative one plus nine is eight.
00:37 So g of negative one is eight.
00:39 For our next evaluation, four, it is less than or equal to four...
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