00:01
We are asked to consider the equation i've written here.
00:02
We are told that we have a 2 .50 liter vessel at 200 and it's filled with no2 at an initial pressure of 2 .75 atms.
00:21
So let's take a look.
00:22
This is going to decrease by 2x, increase by 2x, and decrease by 0 and 0.
00:36
So my final equilibrium concentrations will be 2 .75 minus 2 .75 minus 2x, 2x and 1x.
00:49
My equilibrium expression will be my pressure of no2 squared times my pressure of o2 divided by my pressure of no2 squared.
01:07
Now we can plug our values in.
01:09
Kp was 1 .11 times 10 to the minus 5th.
01:14
And that will equal 2x squared times x over 2 .75 minus x squared.
01:31
Okay, i'm guessing that i will not be able to take any shortcuts on this one...