00:01
The given reaction is ch4 plus 2h2s gas, methane also in gaseous state.
00:12
It will be form ch2 gaseous plus 4h2o.
00:18
Now we have to shift the equilibrium for this reaction to right.
00:30
Now first condition, decrease the concentration of h2s.
00:39
If the concentration of h2s will be decreased, then the equilibrium shift to the lower concentration side as per le chatelier's principle.
01:12
So equilibrium shift left.
01:20
So this is not accepted.
01:23
Now in the second case, if we decrease the pressure of the system, so here delta n will be, here the mole will be 1 plus 4 reactant, 1 plus 4 for the product side minus, for the reactant 1 plus 2.
01:45
So that is 5 minus 3, that will be 2, which is greater than 0.
01:50
So if we decrease the pressure, then moles of product, actually moles of the product is higher.
02:03
So if the pressure will be decreased, we know that pb is equal to constant...