For the reaction, calculate ?G° : 2OPCl3(g) ? 2PCl3(l) + O2(g) ?H° = 508 kJ·mol?¹ and ?S° = 78 J·mol?¹ · K?¹ at 298 K. A. -561 kJ·mol?¹ B. 485 kJ·mol?¹ C. 561 kJ·mol?¹ D. 455 kJ·mol?¹
Added by Gonzalo P.
Close
Step 1
Given values: ΔH = 508 kJ/mol ΔS = 78 J/mol.K T = 298 K We need to convert ΔS to kJ/mol.K: ΔS = 78 J/mol.K ÷ 1000 J/kJ = 0.078 kJ/mol.K Now we can substitute the values into the equation: ΔG = 508 kJ/mol - (298 K)(0.078 kJ/mol.K) ΔG = 508 kJ/mol - 23.284 Show more…
Show all steps
Your feedback will help us improve your experience
John Incabo and 52 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the value of ΔG for a reaction at 298 K if the value of ΔH is -34.2 kJ/mol and the value of ΔS is 133.4 J/(mol*K). Select one: a. -39787.4 kJ/mol b. -73.95 kJ/mol c. +73.95 kJ/mol d. +5.55 kJ/mol e. -5.55 kJ/mol
Dominique Jan T.
Calculate $\Delta G^{\circ}$ at $82^{\circ} \mathrm{C}$ for reactions in which (a) $\Delta H^{\circ}=293 \mathrm{~kJ} ; \quad \Delta S^{\circ}=-695 \mathrm{~J} / \mathrm{K}$ (b) $\Delta H^{\circ}=-1137 \mathrm{~kJ} ; \quad \Delta S^{\circ}=0.496 \mathrm{~kJ} / \mathrm{K}$ (c) $\Delta H^{\circ}=-86.6 \mathrm{~kJ} ; \quad \Delta S^{\circ}=-382 \mathrm{~J} / \mathrm{K}$
Calculate $\Delta S_{\text { urr }}$ at the indicated temperature for each reaction. \begin{equation}\begin{array}{ll}{\text { a. } \Delta H_{\mathrm{rxn}}^{\circ}=-385 \mathrm{kJ} ; 298 \mathrm{K}} & {\text { b. } \Delta H_{\mathrm{rxn}}^{\circ}=-385 \mathrm{kJ} ; 77 \mathrm{K}} \\ {\text { c. } \Delta H_{\mathrm{rxn}}^{\mathrm{o}}=+114 \mathrm{kJ} ; 298 \mathrm{K}} & {\text { d. } \Delta H_{\mathrm{rxn}}^{\circ}=+114 \mathrm{kJ} ; 77 \mathrm{K}}\end{array}\end{equation}
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD