For the reaction C2H4(g) + Cl2(g) ? C2H4Cl2(l), determine ?rH°, given that 4 HCl(g) + O2(g) ? 2 Cl2(g) + 2 H2O(l) ?rH° = -202.4 kJ mol?1 2 HCl(g) + C2H4(g) + 1/2 O2(g) ? C2H4Cl2(l) + H2O(l) ?rH° = -318.7 kJ mol?1
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To do this, we can use the given reactions and their enthalpy changes: 1) 4HCl(g) + O2(g) → 2Clz(g) + 2H2O(l), ΔH1 = -202.4 kJ/mol 2) 2HCl(g) + CzHa(g) + 1/2O2(g) → 2C2H4Cl2(l) + H2O(l), ΔH2 = -318.7 kJ/mol We want to find the enthalpy change for the Show more…
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Find ΔH for the following reaction given the bottom two thermochemical equations. Show all your equation manipulations for full credit. C2H4Cl2 (l) ---> C2H4 (g) + Cl2 (g) ΔH = ? 4 HCl (g) + O2 (g) ---> 2 Cl2 (g) + 2 H2O (l) ΔH1 = -202.4 kJ 2 HCl (g) + C2H4 (g) + ½ O2 (g) ---> C2H4Cl2 (l) + H2O (l) ΔH2 = -318.7 kJ
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