For the reaction: P4O10(s) + 6H2O(l) → 4H3PO4(aq) ΔG° = -448.9 kJ and ΔS° = -16.3 J/K at 262 K and 1 atm. The maximum amount of work that could be done by this reaction when 1.60 moles of P4O10(s) react at standard conditions at this temperature is ________ kJ.
Added by Elizabeth R.
Step 1
9 kJ Maximum work = ΔG° = -448.9 kJ Show more…
Show all steps
Your feedback will help us improve your experience
David Collins and 58 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Tianyu L.
For the reaction 2H2S(g) + 3O2(g) → 2H2O(l) + 2SO2(g), ΔH° = -1124.0 kJ and ΔS° = -390.7 J/K. The maximum amount of work that could be done when 2.17 moles of H2S(g) react at 261 K and 1 atm is ______ kJ. Assume that ΔH° and ΔS° are independent of temperature.
Dominador T.
Calculate $\Delta S_{\text { urr }}$ at the indicated temperature for each reaction. \begin{equation}\begin{array}{ll}{\text { a. } \Delta H_{\mathrm{rxn}}^{\circ}=-385 \mathrm{kJ} ; 298 \mathrm{K}} & {\text { b. } \Delta H_{\mathrm{rxn}}^{\circ}=-385 \mathrm{kJ} ; 77 \mathrm{K}} \\ {\text { c. } \Delta H_{\mathrm{rxn}}^{\mathrm{o}}=+114 \mathrm{kJ} ; 298 \mathrm{K}} & {\text { d. } \Delta H_{\mathrm{rxn}}^{\circ}=+114 \mathrm{kJ} ; 77 \mathrm{K}}\end{array}\end{equation}
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD