For the reaction PCl_5(g) ⇌ PCl_3(g) + Cl_2(g) at equilibrium, K_p = 321. The equilibrium partial pressures of PCl_3 and Cl_2 are 1.11 atm and 4.39 atm, respectively. What is the equilibrium partial pressure of PCl_5?
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Step 1: Write down the equilibrium expression for the reaction: K_p = [PCl3] * [Cl2] / [PCl5] Show more…
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