For the reaction pclg pclg clg at equilibrium k 321 the...

Name: for the reaction pclg pclg clg at equilibrium k 321 the equilibrium partial pressures of pcl and cl are 111e0 atm and 439e0 atm respectively what is the equilibrium partial pressure of pcl 38975
Uploaded: 2022-06-15T09:06:17-08:00
Duration: 1 min 2 s
Channel: Shaiju T
Description: for the reaction pclg pclg clg at equilibrium k 321 the equilibrium partial pressures of pcl and cl are 111e0 atm and 439e0 atm respectively what is the equilibrium partial pressure of pcl 38975

For the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g) at equilibrium, K = 321. The equilibrium partial pressures of PCl3 and Cl2 are 1.11E0 atm and 4.39E0 atm, respectively. What is the equilibrium partial pressure of PCl5?

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The equilibrium constant $\left(K_{P}\right)$ for the reaction $\mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{PCl}_{5}(g)$ is 2.93 at $127^{\circ} \mathrm{C}$ Initially there were 2.00 moles of $\mathrm{PCl}_{3}$ and 1.00 mole of $\mathrm{Cl}_{2}$ present. Calculate the partial pressures of the gases at equilibrium if the total pressure is $2.00 \mathrm{atm}$

The equilibrium constant $K_{P}$ for the reaction $$ \mathrm{PCl}_{5}(g) \rightleftharpoons \mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) $$ is 1.05 at $250^{\circ} \mathrm{C}$. The reaction starts with a mixture of $\mathrm{PCl}_{5}, \mathrm{PCl}_{3},$ and $\mathrm{Cl}_{2}$ at pressures 0.177 atm, 0.223 atm, and 0.111 atm, respectively, at $250^{\circ} \mathrm{C}$ When the mixture comes to equilibrium at that temperature, which pressures will have decreased and which will have increased? Explain why.

Transcript

00:01 Hello students, so in the question we have been given a reaction.

00:05 Pcl5 gives pcl3 plus cl2 gas.

00:09 We have to find the equilibrium partial pressure.

00:11 The k equivalent given is 321.

00:15 The k equivalent expression for this case will be the partial pressure of pcl3 multiplied by the partial pressure of cl2 divided by that of reactant, that is partial pressure of pcl5.

00:27 We have the value of every except the pcl5...

Question

For the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g) at equilibrium, K = 321. The equilibrium partial pressures of PCl3 and Cl2 are 1.11E0 atm and 4.39E0 atm, respectively. What is the equilibrium partial pressure of PCl5?

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