For the reaction shown below, select the expected major product. 1. excess NaNH2 2. H2O I II III IV V
Added by William T.
Close
Step 1
NaNH2 is a strong base, so it will deprotonate the terminal alkyne (C≡CH) to form an acetylide ion (C≡C⁻). Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 60 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For the following reaction, select the major product below:
Madhur L.
For the following reaction, the major product is:
Carbonyl Compounds II (Grignard Reagent and Name Reactions)
JEE (Main) Exercises
Consider the following reaction: what is the expected product? NH2 Br2, H2O NH2 Br Br Cl Br Br H2N Cl NH2 NH2 Br NH2 Br Br Cl
Sri K.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD