00:01
Hi, so we are to calculate the amount of the products to form based on the given amount of the reactant.
00:09
So, let's start with nacl.
00:11
If we have 11 .0 grams of hcl, convert this to moles by dividing the molar mass of hcl.
00:18
36 .46 grams, then we have here moles of hcl.
00:22
As per our balance equation, for every 2 moles of hcl, we'll have 2 moles of nacl formed.
00:34
And then multiply the molar mass of nacl, 58 .44 grams here and then moles in here.
00:41
Then we cancel some units, grams, moles of hcl, moles of nacl, and the remaining unit should be grams of nacl.
00:49
So we'll have 17 .6 grams of nacl.
00:53
This is our answer to the first question.
00:56
And then the others still have water.
01:01
So same process, convert hcl to moles, divide the molar mass, moles of hcl, and as per balance equation, 2 moles of hcl, it will form 1 mole of h2o.
01:18
Then multiply the molar mass of water, 18 .02 grams here and then moles in here.
01:26
So now we can cancel some units and we'll get 2 .72 grams of h2o.
01:38
For co2, 11 .0 grams of hcl, convert to moles, 36 .46 grams, and we have here moles of hcl.
01:49
As per balance equation, 2 moles of hcl will form 1 mole of co2.
01:57
Multiply the molar mass of co2, 44 .01 grams here and then moles in here.
02:03
Cancel some units, grams, moles of hcl, moles of co2, and we'll get 6 .64 grams of co2...