For the scattering of 0.1MeV electrons off 119Sn nuclei, calculate the relative size of the relativistic correction to the differential scattering cross section for scattering angles of 20° and 90° Repeat this part for 1Mev and 100 MeV electrons
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1 MeV electrons at a scattering angle of 20°. Given: Energy of electrons (E) = 0.1 MeV = 0.1 x 10^6 eV Scattering angle (θ) = 20° Calculate the wave number (k): k = 2 * √(E * (E + 2m)) where m is the rest mass of the electron m = 0.511 MeV/c^2 k = 2 * √(0.1 * 10^6 Show more…
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