For the slanted surface E in Figure 1, show the unit normal for E is: n_E = 1 / sqrt(0.5^2 + 0.7^2) (0.7 j^ + 0.5 k^) z C (back) B (side in yz plane) 130 cm y E (slanted front) 70 cm D (bottom) 50 cm A (near side) x Figure 1
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7j + 0.5k, we have: |n| = sqrt(0.7^2 + 0.5^2) |n| = sqrt(0.49 + 0.25) |n| = sqrt(0.74) Show more…
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