00:01
In this particular question we have three parts part a b and c okay so first we will calculate the magnitude of tension for part a okay now for the force equation is f a is equal to w minus f t now also one of the equation will be f b is equals to f e and arthur will be t minus f h is equal to z moving forward, excuse me, this can be also written as w.
00:40
L.
00:40
Cos theta minus f fe l cos theta minus w.
00:52
L minus d cost theta minus w.
01:00
L minus d x times l over 2, sine theta is equal to 0.
01:08
Simplifying this we will have f .e times l cos theta minus t times l over 2, sine theta as it is to be here.
01:24
Simplifying this further.
01:30
F .e is equal to t sine theta over 2 cost theta, t over 2 times tan theta.
01:45
W times t over l times tan theta.
01:52
Now l is equals to root over 3 .3.
01:55
0 .06 over plus 0 .846 over 2 square over 2 whole square root over this is equals to exactly after simply find 1 .587 meters now simplifying this further we will have tan theta equal to 1 .587 over 0 .846 over 2 if this is equals to 3 .7527...