00:02
Hi, here in this given problem, three coupled coils, mutually coupled coils are in series.
00:13
And shown like this.
00:15
The first one is having self -inductance 6 henry, 2nd 1, 8 henry, 3rd 1, 10 henry.
00:24
Then mutual inductance between 1st and 2nd, that is 4 henry, between 2nd and 3rd, between 2nd and 3rd, this is 5 henry and mutual inductance between first and third that is given as 2 henry.
00:47
Now we have to find the net inductance.
00:52
First of all for coil 1, it will be equal to self inductance of the first coil minus its mutual inductance with the second one and then plus its mutual inductance with the third one.
01:14
So here it will be 6 minus 4 but plus 2.
01:20
So combinedly it comes out to be 4 henry.
01:23
Then for the second coil 2 this is l2 minus m of 2 with respect to 1 minus m of 2 with respect to 3...