00:01
But you're a student, so let's move to part a.
00:06
First, let's solve for the time from zero seconds to four seconds, right? we know that the velocity is equal to rate of change of displacement or rate of change of the position, right? so if we want position, then it means that we have to integrate the velocity with respect to the time.
00:43
All right.
00:44
So let's integrate this.
00:50
Dx would be equal to x, that is the position.
00:54
That equals integration of vx from 0 to 4 seconds, seconds is given.
01:01
That is minus 3 meters per second into d t.
01:07
The lower limit should be 0 seconds.
01:09
The upper limit should be 4 seconds.
01:11
So from here the position equals minus 12 meters all idea student so for the time from four to six seconds so the time from four to six seconds right this is for my dear student all right six is not included here in this limit so four to six we would we would do the same that we would integrate the velocity from four to six seconds and from 4 to 6 seconds, the velocity here is given that is positive 3 meters per second.
02:02
Right.
02:03
So this was negative, right? so from here, the position or the displacement from 4 to 6 seconds equals there is 6 meters, mario, student.
02:17
Finally, for the time greater than 6 seconds.
02:24
So time greater than six seconds the displacement equals one meters per second the velocity from t to infinity.
02:46
T is equal to six seconds to infinity.
02:50
This is one meters per second the velocity is.
02:55
So from here the position equals maria student.
03:01
That equals let's say the upper limit is t2...