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In this problem, we are given that there are two events a and b such that the probability of the event a, this is equal to 0 .6 and the probability of the event b, well, that's equal to 0 .3.
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The two events a and b, they are independent events and we have to compute the conditional probability of a given b as well as the conditional probability of b given a.
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So first, we see that the two events are independent.
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This means that the probability of a intersection b, that will be the product of the probabilities of the two events.
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And let's use this formula, according to which we see that the conditional probability of a given b is obtained when we divide the probability of a intersection b with the probability of the event b.
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So doing that, we will get this as probability of the event a, which is 0 .6.
00:56
And next, we find the probability of b given a...