00:01
Okay, so i'm going to explain which one is more reactive toward nucleophilic condition.
00:05
And this is just a nucleophile attacking the carbon of the carbonyl to add to that carbon atom.
00:12
And the first one is 2 -2 -diamethyl perpinol compared to peripanol.
00:18
And peripanol is just a 3 -carbon aldehead.
00:22
Then 2 -2 -dymethyl, we're going to have methyl on carbon -2.
00:28
And this is going to be less reactive because the carbon of the carbonyl is less accessible to nucleophil attack.
00:35
Due to the addition of these bulky methyl groups it'll make it harder for the nucleophile to come in and attack the carbon of the carbeneal so one reason is less accessible another reason is that the the r groups or the methyl groups are electron donating and they're going to make this carbon more electronegative and as a result it's also going to affect the carbon of the carbonyl as well and we want this carbon of the carbonyl to be as electrophil as possible to be attacked by the nucleophile.
01:17
And if it's more electronegative, it's going to be less electrophilic.
01:24
So you can see the presence of electron dony groups or edj.
01:37
Next one is paramythoxy benzaldehyde compared to perinitur binzadad.
01:43
But for the first one, another thing to note is that the hydrogen doesn't really contribute any election negatively to the carbon atom, and therefore it's not going to affect.
01:52
It's only going to make it more accessible.
01:55
But it's not going to donate any electronegativity.
02:01
So benzaldehyde is an aldehyde attached to a benzene ring, and the nitro group is no2, and para is four carbons away, relative to the parent -the -parent -susituate, and mythoxy group is an ether, and it's also electron donating, so it's going to make, through resonance, it's going to make this carbon more electronegative and less electrophilic.
02:37
So, lecture of felicity and electro -negativity, are inversely proportional as one goes up, the other goes down.
02:46
So this auction of the methoxy group can use a pair of electrons to form bond right there...