Question

For $f(x) = -5\sqrt{3x + 2}$ $g(x) = 4\sqrt{1 - x}$ $h(x) = \frac{x + 8}{x^2 - x - 6}$ $p(x) = \sqrt[3]{x - 2}$ $w(x) = x - 5$ Find $(p \circ f)(1)$ 0 $\sqrt{5 - \sqrt[3]{2}}$ -5 $\sqrt[3]{-5\sqrt{5} - 2}$ doesn't exist

          For $f(x) = -5\sqrt{3x + 2}$
$g(x) = 4\sqrt{1 - x}$
$h(x) = \frac{x + 8}{x^2 - x - 6}$
$p(x) = \sqrt[3]{x - 2}$
$w(x) = x - 5$
Find $(p \circ f)(1)$
0
$\sqrt{5 - \sqrt[3]{2}}$
-5
$\sqrt[3]{-5\sqrt{5} - 2}$
doesn't exist

For f(x) = -5√(3x + 2)
g(x) = 4√(1 - x)
h(x) = (x + 8)/(x^2 - x - 6)
p(x) = √(x - 2)
w(x) = x - 5
Find (p ∘ f)(1)
0
√(5 - √(2))
-5
√(-5√(5) - 2)
doesn't exist

Added by Joshua J.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Maria Dearborn

Step 1

To do this, we substitute x = 1 into the function f = -53x + 2: f(1) = -53(1) + 2 = -53 + 2 = -51. Show more…

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For f = -53x + 2, g = 41 - x p(x) = x - 2 w(x) = x - 5 Find (p o f)(1) 0 5 - 2 0 - 5 5^5 - 2 O doesn't exist

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Question

For $f(x) = -5\sqrt{3x + 2}$ $g(x) = 4\sqrt{1 - x}$ $h(x) = \frac{x + 8}{x^2 - x - 6}$ $p(x) = \sqrt[3]{x - 2}$ $w(x) = x - 5$ Find $(p \circ f)(1)$ 0 $\sqrt{5 - \sqrt[3]{2}}$ -5 $\sqrt[3]{-5\sqrt{5} - 2}$ doesn't exist

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