B REPORT FORM: DYNAMICS OF A ROLLING CART Data Table...

B REPORT FORM: DYNAMICS OF A ROLLING CART Data Table 503.09 Mass of cart: 0-503 kg. Mass of bar: 0-49429kg M? = Mass of cart + Mass of bar: 099729 kg 494.29 9 Mass of 'weight hanger': 0.005 kg. Note: M2 = mass of 'weight hanger'+ added masses 59 Trial # M2 (kg) Acceleration a (m/s²) (M1+ M2) a (N) 1 0.01 kg 0.063 0.063 2 0.015 kg 0.105 0.106 3 0.02 0.140 0.142 4 0.025 0.187 0.191 5 0.03 0.215 0221 6 0.035 0.280 0.289 7 0.04 0340 0.353 8 0.045 0.380 6.396 9 0.05 0.413 0.432 10 0.055 0.462 0.486 Graph: Plot (M1 + M2) a versus M2. Label the graph appropriately. Please show your graph.

Transcript

00:01 The question is draw a free body diagram for a cart moving toward the pulley at a constant velocity and the cart is moving in positive x direction.

00:11 Label the mass of cart as mc indicate the direction of all velocity and acceleration on your free body diagram and calculate the magnitude of the frictional force on the cart in terms of mc and a.

00:25 So now firstly we have to draw the free body diagram.

00:29 The free body diagram for the card is it is the table where here it is card.

00:43 The mass of card is mc and here we have a pulley and here is the hanging mass.

00:58 And it move in this direction.

01:00 It is a means acceleration.

01:03 V is the velocity and here is positive x direction, negative x direction plus v.

01:14 Plus y and minus y so but we have given given mass of cart the mass of cart mc is 0 .297 kg hanging mass 0 .005 kg and acceleration acceleration of cart is 0 .233 meter per second and we have to find the friction force we have to find the frictional force so firstly we draw the free body diagram for the above situation free body diagram cart the weight of cart is acting vertically downward and it is w is equal to m c into g here we have tension force here we have friction force and upward we have a normal direction and the acceleration is very much positive in positive x direction so free body diagram it is for cart and a free body diagram for hanging mass for hanging mass tension in upward direction and weight vertical downward acting firstly equation of motion we write the equation of motion so for this equation of motion we can write equation of motion.

03:47 So firstly, t is in forward direction and f is in backward direction.

03:54 T minus f and is equal to the force...

Question

Please give Ace some feedback