Formally prove that log(n!) = O(nlogn)
Added by Alisha A.
Step 1
It is the logarithm of the factorial of n, which is the product of all positive integers up to n. We can write log(n!) as the sum of logarithms of all positive integers up to n, because the logarithm of a product is the sum of the logarithms of the factors. So, Show more…
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