Question

Four ions (Na+, Cl-, Na+, and Cl-) in a row are each separated from their nearest neighbor by 3.0×10^-10 m. The charge of a sodium ion is +e and that of a chlorine ion is -e. Part A Determine the electric force exerted on the chlorine ion at the right end of the row due to the other three ions. (+x to the right) Express your answer with the appropriate units. Fq = Value Units

          Four ions (Na+, Cl-, Na+, and Cl-) in a row are each separated from their nearest neighbor by 3.0×10^-10 m. The charge of a sodium ion is +e and that of a chlorine ion is -e.

Part A
Determine the electric force exerted on the chlorine ion at the right end of the row due to the other three ions. (+x to the right)
Express your answer with the appropriate units.
Fq = Value Units

Four ions (Na+, Cl-, Na+, and Cl-) in a row are each separated from their nearest neighbor by 3.0×10^-10 m. The charge of a sodium ion is +e and that of a chlorine ion is -e.

Part A
Determine the electric force exerted on the chlorine ion at the right end of the row due to the other three ions. (+x to the right)
Express your answer with the appropriate units.
Fq = Value Units

Added by Mark S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Reema C

03/04/2022

Step 1

6 \times 10^{-19}) \cdot (-1.6 \times 10^{-19})|}{(3 \times 10^{-10})^2} \] \[ F_1 = \frac{9 \times 10^9 \cdot 2.56 \times 10^{-38}}{9 \times 10^{-20}} \] \[ F_1 = 2.56 \times 10^{-18} \, N \] Show more…

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Four ions (Na+, Cl-, Na+, and Cl-) in a row are each separated from their nearest neighbor by 3.0x10^-10 m. The charge of a sodium ion is +e and that of a chlorine ion is -e. Part A: Determine the electric force exerted on the chlorine ion at the right end of the row due to the other three ions. (+x to the right) Express your answer with the appropriate units.