00:01
Hi, here in this given problem there are the four parallel current carrying conductors which are arranged at the four corners of a square.
00:17
The conductor, first conductor kept at the vertex a, it is carrying current perpendicular to the plane of paper directed into it.
00:29
Another one which is put at b that is also carrying the current directed into the plane of paper the third one at c it is carrying current coming out of the plane of paper and the last one at d it is also carrying current coming out of the plane of paper then there is a point at the center of this square p we have to find net magnetic field at this point p current in all these four conductors having same magnitude 6 .33 ampere side of the square that is 0 .200 meter so length of the diagonal that will be side root 2.
01:46
So, distance of center p from all the current carrying conductors, that will be equal to half of the diagonal a root 2 by 2 means this is 0 .200 meter into 1 .414.
02:21
And divided by 2.
02:23
So this is 0 .141 meter.
02:29
Now to find net magnetic field here at point p the directions of the magnetic fields at point p due to all four straight current carrying conductors is as shown here in the figure and these directions are found using right -hand thumb rule.
03:36
So first of all, direction of magnetic field at p due to this conductor put at a if we use right -hand thumb rule, the magnetic field at p will be this.
03:50
This is b due to a and then magnetic field due to b that will be towards d.
04:03
This is b due to b.
04:06
Then magnetic field due to c...