Four people are chosen at random. What is the probability (expression only) that at least two of them were born in the same month? Assume that each month is as likely as any other
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Step 1
Step 1:** Calculate the total number of ways to choose 4 distinct months out of 12 months using the permutation formula: \[ \text{Total ways} = \frac{12!}{(12-4)!} = \frac{12 \times 11 \times 10 \times 9}{1} = 11,880 \] ** Show more…
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