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Question 7.
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Let r1, r2, r3 and r4 be the four resistors that are connected in parallel.
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In a network of parallel resistors, the reciprocal of the total resistance can be written as the sum of the reciprocal of the individual resistance.
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Let's call this equation 1.
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Now let r1 be the smallest resistance.
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Now we can say that 1 over r1 is greater than 1 over r2, 1 over r3 and 1 over r4.
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Thus 1 over r1 plus 1 over r2 plus 1 over r3 plus 1 over r4 must put be greater than 1 over r1.
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The left -hand side can also be written as 1 over r total, which is greater than 1 over r1.
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This implies that the total resistance must be lesser than the smallest resistance.
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Question 8.
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In this question, 2 -om resistance is connected in series with another 2 -oom resistance.
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And for series connection, we know that the net resistance can be written as the sum of the individual resistance, which is 2 oom plus 2 oom, which is equal to 4 oom.
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Now, the given circuit as 4 oom connected in parallel with 2 oom, which is connected in parallel with another 4 ome resistance.
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For a parallel circuit, the reciprocal of the net resistance can be written as 1 over 4 oom plus 1 over 2 oom plus 1 over 4 oom...