00:01
Hi, here there are three different problems, three different questions in this given problem.
00:07
In the first one there are four light disks and as the disks are massless, so moment of inertia will be provided by only, will be provided only by, only by, provided only by, the heavy marbles.
01:00
Suppose each of the marble is having a mass m and radius of the disk.
01:33
Suppose that is r.
01:38
So moment of inertia of the first disk as all the three marbles at the circumference of the disk so that will be m r squared plus m r square plus m r square means that is 3 m r square then i b moment of inertia of the disk b as all three marbles are glued near to the center only so we may consider moment of inertia of the disk b to be equal to 0 then for disc see there are two marbles at the circumference one marble is at the point of rotation center of rotation so its moment of inertia will not contribute so that will be only 2 m r square and finally i d here that is m r square for the marble glued at the center and m into 2 r square for the marble glued at the opposite end on the circumference.
02:59
So it comes out to be equal to 5 m r squared.
03:03
So the decreasing order of the moments of inertia of all these disks, that is, i, d is largest, which is greater than ia, further greater than ia, further greater than i, i c and greater than i b.
03:22
So we can say here last option looks to be correct...