00:01
Shown here is the given figure from the problem.
00:04
We have an apple one that is dropped from a bridge of a height that just let's denote as why not and falls to the ground at a height y, which is equals to zero.
00:17
And the time of light is equal to two seconds.
00:21
Then we have apple two that is thrown at some later time and the total time of light let's denote as t2.
00:28
Now, question, now the question is, as as what is the initial velocity of apple 2.
00:38
So to determine the initial velocity of apple 2, we must find first the initial height.
00:53
So we can drive an expression for the initial height from the equation of motion of apple 1.
00:59
So we have y1 is equals to y0 1 plus v0 y0 .1 t1 plus 1 half a y1 t1 squared.
01:24
And since it's a projectile motion, the vertical acceleration of upper 1 is equals to negative g.
01:33
And since it's what stated that it was just dropped, then the initial velocity is equal to 0.
01:43
And we know that the final height is equals to 0.
01:51
Then our equation becomes like this.
02:00
Then solving, we know that acceleration due to gravity is 9 .8 meter per second squared.
02:10
And the total time of flight of apple 1 is 2 seconds.
02:14
So solving, we can find that the initial height of both apples is 19 .6 meters.
02:21
Now, we can use this initial height for the equation of motion for apple 2...