00:01
Hello everyone, we are going to understand this question.
00:05
Here in the question there is given a circuit diagram and based on the given circuit diagram and data we have to find the answer of the given question.
00:16
From the data given in the circuit diagram, from the data given in circuit diagram we can write we have to find the equivalent resistance.
00:37
So here we can see that r2 and r4 on series, r2 and r4 are in series.
00:43
So, equal the equivalent of r2 and r4 is equal to r2 plus r4.
00:50
Here r2 is 15 om and r4 is 15 ome.
00:55
So after calculation we will get 30 ome.
00:58
Now it is combinedly parallel with r3.
01:01
So r3 -24 that is combined equivalent of r3, r2 and r5 is.
01:14
So it is in parallel so we can write 1 upon r2 plus 1 upon r3.
01:19
Sorry here by mistakenly we can write 1 upon r3 plus 1 upon r24 now substituting the value in this here value of r3 is 20 value of r24 that is 30 so after calculation we will get r3 24 that will give 60 upon 5 means 12 oom now r1 r1 r3 24 and r5 are in series.
01:59
So, r equivalent is equal to r1 plus r3 obliq 24 plus r5.
02:11
Now substituting the value in this r1 is 20 ome, r3 obliq 24 that is 12 ome plus r5 that is 8 ome.
02:23
So after calculation we will get 40 om, r equivalent that is 40 om.
02:35
Now in the part we have to find the current through each register.
02:41
So let current in r1 is i1, current in r2 is i2 and current in r3 is i3.
02:51
Now in this circuit also there will be i1 because total current is flowing in the circuit is i1 and i1 current is going from battery and it will return to the same at the battery at the second end of the battery so so we can write first of all we will calculate the total current total current in the circuit total current in circuit that is i1 is equal to v upon r equivalent here value of v is 12 volt and r equivalent that is 40 now after calculation we will get i i i 1 is equal to 0 .3 ampere now we will find the potential drop across r1 and r5.
03:56
Potential drop across r1 that is 0 .3 into r1.
04:09
So 0 .3 into r1 is 20.
04:12
So after calculation we will get 6 volt.
04:15
And potential drop across r3.
04:22
Potential drop across, sorry, across r5, that is i1 into r5, value of i1 is 0 .3 and value of r5 is 8 so after calculation we will get 2 .4 volt hence potential drop across hence potential drop across r3 that is that is v minus v1 minus v5 so value of v that is 12 value of v1 that we have already calculated 6 and value of v5 that is 2 .4 so after calculation we we will get 3 .6 volt.
05:27
So potential drop across 3 home resistance, 3 home resistor that is 3 .6 volt...