Question

From the equation expressing the law of radioactive decay, derive the following useful formulas for the decay constant and the half-life, in terms of the time interval $\Delta t$ during which the decay rate decreases from $R_{0}$ to $R$ : $$ \lambda=\frac{1}{\Delta t} \ln \left(\frac{R_{0}}{R}\right) \quad T_{1 / 2}=\frac{(\ln 2) \Delta t}{\ln \left(R_{0} / R\right)} $$

          From the equation expressing the law of radioactive decay, derive the following useful formulas for the decay constant and the half-life, in terms of the time interval $\Delta t$ during which the decay rate decreases from $R_{0}$ to $R$ :
$$
\lambda=\frac{1}{\Delta t} \ln \left(\frac{R_{0}}{R}\right) \quad T_{1 / 2}=\frac{(\ln 2) \Delta t}{\ln \left(R_{0} / R\right)}
$$
        
Show more…

Added by John T.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
From the equation expressing the law of radioactive decay, derive the following useful formulas for the decay constant and the half-life, in terms of the time interval $\Delta t$ during which the decay rate decreases from $R_{0}$ to $R$ : $$ \lambda=\frac{1}{\Delta t} \ln \left(\frac{R_{0}}{R}\right) \quad T_{1 / 2}=\frac{(\ln 2) \Delta t}{\ln \left(R_{0} / R\right)} $$
Close icon
Play audio
Feedback
Powered by NumerAI
David Collins Kathleen Carty
Jennifer Stoner verified

Sri K and 78 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
from-the-equation-expressing-the-law-of-radioactive-decay-derive-the-following-useful-expressions-fo

From the equation expressing the law of radioactive decay, derive the following useful expressions for the decay constant and the half-life, in terms of the time interval $\Delta t$ during which the decay rate decreases from $R_{0}$ to $R :$ $$\lambda=\frac{1}{\Delta t} \ln \left(\frac{R_{0}}{R}\right) \quad T_{1 / 2}=\frac{(\ln 2) \Delta t}{\ln \left(R_{0} / R\right)}$$

Physics for Scientists and Engineers with Modern Physics

the-half-life-of-a-radioactive-material-is-the-time-required-for-an-amount-of-this-material-to-decay-to-one-half-its-original-value-show-that-for-any-radioactive-material-that-decays-accordi-76157

The half-life of a radioactive material is the time required for an amount of this material to decay to one-half its original value. Show that for any radioactive material that decays according to the equation Q' = -rQ, the half-life t and the decay rate r satisfy the equation rt = ln 2.

Sam S.

start-with-equation-1310-and-find-the-following-useful-forms-for-the-decay-constant-and-half-life-la

Start with Equation $13.10,$ and find the following useful forms for the decay constant and half-life: $$\lambda=\frac{1}{t} \ln \left(\frac{R_{0}}{R}\right) \quad T_{1 / 2}=\frac{(\ln 2) t}{\ln \left(R_{0} / R\right)}$$

Modern Physics


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,105 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,600 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,152 solutions

*

Transcript

-
00:01 So from here we know that the formula for the decay rate or the activity of a radio active substance is r that is equal to r node multiplied by the a a raise to the power minus of lambda of dell of t so from here r divided by the r node is equal to e raise to the power minus of lambda of del t so from here taking log on both sides so minus lambda of del of t…
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever