From the following data on an enzymatic reaction, determine (a) the type of inhibition, (b) KM for the substrate, and (c) KI for the inhibitor-enzyme complex. Substrate concentration, mM Product per hour,
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We have substrate concentrations and the corresponding product formation rates per hour, both without an inhibitor and with a 6 mM inhibitor. - Without inhibitor: - Substrate concentration (mM): 2.0, 3.0, 4.0, 10.0, 15.0 - Product per hour: 139, 179, 213, Show more…
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The following graph shows how the rate of an enzymatic reaction is affected by substrate concentration: a) Using the above graph, determine Vmax and KM for this enzyme (according to Michaelis-Menten kinetics). 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0 100 200 300 400 500 600 700 Reaction rate (mM/s) Substrate concentration (mM) b) In the presence of an inhibitor, the values of Vmax=0.3 mM/s and KM=10 mM have been obtained. What type of inhibition has occurred?
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