00:01
Part a asked to show that the time average intensity as a function of the angle theta is some expression.
00:07
So, the individual amplitudes of the waves for e1, e2, and e3 can be written as follows.
00:16
E1 is e0 sine omega -t, e2 is e0 -sine omega -t plus 5, and e3 is equal to e0 -sine omega -t plus 2 -5.
00:26
So the result in amplitude is equal to e1 plus e2.
00:30
Plus e3.
00:32
So we can add these together.
00:34
And here, phi is 2 pi divided by lambda times d sine theta.
00:41
So we can go ahead and plug that in for phi and start expanding everything out.
00:46
Then we'll have this very long expression for er, which er is equal to e0, um, as sine omega t plus sine omega t cosine five plus cosine omega t sine omega t sine five, plus sine omega t cosine 2 5 plus cosine omega t sine of 2 5 after expanding all of these out.
01:06
We can go ahead and apply some properties of cosine and sign to reduce this.
01:12
So we'll have e0 sine omega t times 1 plus cosine 5 plus 2 cosine 5 plus 2 cosine squared 5 minus 1 plus e0 cosine omega t times sine 5 plus 2 sine 5 cosine cosine 5.
01:29
This can be simplified even further to e0 is times 1 plus 2 cosine phi, sine omega -t plus phi.
01:38
So this is our simplified expression...