quadratic function. f(x) = ?(x + 1)² + Part 1 - Intercepts ? Part 2 - Standard Form
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To find the x-intercept, we set y = 0 and solve for x: 0 = -(x + 1)^2 0 = x + 1 x = -1 Therefore, the x-intercept is (-1, 0). To find the y-intercept, we set x = 0 and solve for y: y = -(0 + 1)^2 y = -1 Therefore, the y-intercept is (0, -1). Show more…
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