00:01
Okay, so this problem is a limiting reactant problem.
00:04
So we're going to start with what we know, and we're going to convert both of them, both of our reactants to our product.
00:11
Now we need to note that the equation is not yet balanced, so we need to balance it.
00:16
So we have four carbon, so we need four co2.
00:28
Two out front here, which means we need to multiply everything by two.
00:32
I wrote this really small.
00:35
So sorry.
00:36
So this is going to be eight co2.
00:41
This is going to be 10 h2o, and then we have 10 plus 8 times 2 is 16, so 26, and 26 divided by 2 is 13.
00:55
Okay, so now we have a balanced reaction, so now we can proceed forward with the stoichiometry.
01:00
So we're going to start with the 1 .2 grams of c4h10.
01:10
So if we start with grams of c4h10, grams of c4h10, let's go on the bottom.
01:16
One mole of c4h10 is going to go at top.
01:22
The molar mass of c4h10 is 58 .14.
01:27
The second thing to do is go mold to mole.
01:30
So we're going to go from moles of c4h10 to moles of co2.
01:38
When we go from mold to mole, we need to look at the coefficients.
01:41
The coefficient of co2 is 8, while the coefficient of c4h10 is 2.
01:47
Last but not least, we need to go to grams...