Question

Genetics Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 68 A's in the 20th position. You can use the Distribution Calculators page in SALT to find critical values and/or p-values to answer parts of this question. Please note that the Inferential Statistics page does not use the continuity-corrected version of the test statistic. (a) If the probability of an A in the 20th position in ribosomal 5S RNA is 0.79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method. (Use $\alpha = 0.05$.) State the null and alternative hypotheses. (Enter != for $\neq$ as needed.) $H_0$: $H_1$: Find the test statistic. (Round your answer to two decimal places.) Find the critical value. (Round your answer to two decimal places.) State your conclusion. O Reject $H_0$. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Fail to reject $H_0$. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Reject $H_0$. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Fail to reject $H_0$. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. (b) Use technology to report a p-value corresponding to your results in (a). (Round your answer to four decimal places.) p-value =

          Genetics
Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 68 A's in the 20th position.
You can use the Distribution Calculators page in SALT to find critical values and/or p-values to answer parts of this question. Please note that the Inferential Statistics page does not use the continuity-corrected version of the test statistic.
(a) If the probability of an A in the 20th position in ribosomal 5S RNA is 0.79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method. (Use $\alpha = 0.05$.)
State the null and alternative hypotheses. (Enter != for $\neq$ as needed.)
$H_0$:
$H_1$:
Find the test statistic. (Round your answer to two decimal places.)
Find the critical value. (Round your answer to two decimal places.)
State your conclusion.
O Reject $H_0$. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
O Fail to reject $H_0$. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
O Reject $H_0$. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
O Fail to reject $H_0$. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
(b) Use technology to report a p-value corresponding to your results in (a). (Round your answer to four decimal places.)
p-value =

genetics ribosomal 5s rna can be represented as a sequence of 120 nucleotides each nucleotide can be represented by one of four characters a adenine g guanine c cytosine or u uracil the char 49219

Added by Nerea P.

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