00:01
In this problem, we're given that the perimeter of a rectangle is 86 units, and we're told that the length is one more than the square of the width, and then we're asked to find the area.
00:14
So first we're going to use the perimeter formula to help us find out those dimensions.
00:19
So since i know the perimeter is 86, i'm going to write 86 equals 2 times l.
00:27
But remember l is that w square plus 1 plus 2 times the width.
00:38
And let's do some simplifying.
00:40
We get 2w square plus 2 plus 2w.
00:45
And let's take everything to one side, set that equal to 0.
00:50
So we have 2w square plus 2w minus 84 equals 0.
00:57
Since those are, coefficients are all even numbers, let's divide everything by two.
01:03
We get w squared plus w minus 42 equals zero.
01:09
We need two factors of negative 42 that add up to positive 1...