1) Given: \overline{AB}, P not on \overline{AB}\\ Construct \overline{PQ} so that \overline{PQ} \perp \overline{AB}\ a)\\ \qquad A \qquad \qquad B\ c)\\ \qquad A \qquad P \qquad B\ 2) Given: \overline{AB}\ Construct: \overline{PQ} so that \overline{PQ} \perp bisector of \overline{AB}\ a)\\ \qquad A \qquad B\ b)\\ \qquad A \qquad B\ c)\\ \qquad A \qquad B\ d)\\ \qquad A \qquad B
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Given a point T break and point P6 1 TE: This means that there are two points, T and P6, and they are connected by a line segment TE. Show more…
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