00:01
This problem says give the equation of the perpendicular bisector of the segment pq where p is negative two five and q is six seven.
00:08
And to write this equation we are going to attempt to write it in slope intercept form which is y equals mx plus b.
00:14
So we'll need two things the slope and the y -intercept.
00:18
Our slope can be found by using our slope formula y2 minus y1 over x2 minus x1.
00:24
So here we'll say x1 and y1 are negative two five and x2 y2 are six seven.
00:31
So y2 seven minus x1 or excuse me y1 five divided by x2 six minus x1 negative two.
00:40
That gives us the slope of two over six plus two which is eight and that simplifies to one fourth.
00:48
And that's the slope of the segment that would connect our points.
00:52
But we don't want the same slope because that would make it parallel to this segment.
00:55
We want the perpendicular slope and perpendicular slopes are negative reciprocals of each other.
01:00
So that means we're going to flip one fourth to become four over one and change it from a positive slope to a negative slope.
01:08
So our slope we know now has to be negative four but what we don't know is the y -intercept...