00:01
Hi there.
00:02
In this question, we want to know the general formula for a cyclic alken.
00:07
Let's start first with a cyclic alkan.
00:12
Because that is one that i know off the top of my head.
00:16
I know that a cyclic alcane has the general formula c to the n, h to the 2n.
00:26
So if we have a cyclic alken, that means we have a double bond in there, which means we have lost two hydrogen.
00:36
So if we lose two hydrogen, it's going to be c to the n, h to the 2n, minus 2.
00:47
So that appears to be our answer, but we can also double check this by sketching it out.
00:53
If you get no cyclic alkan, another way you could do this then is to just sketch it out.
01:00
So let me grab any old cyclic alken here.
01:04
I'll do one with five carbons.
01:10
Okay.
01:11
Let me add some hydrogens here.
01:13
This carbon and this carbon only need one hydrogen each to make a total of four bonds...