00:01
Hello students, let's look at the questions.
00:01
So here's some structures are given.
00:04
This is the one structure that is given and this is the second structure.
00:13
This one is third structure over here.
00:18
This is the fourth one and this is last and fifth structure.
00:29
So for the iupac name, firstly, we will select the longest carbon chain.
00:36
So let's start numbering.
00:37
This is would be one, two, three, four, five, six.
00:43
And from this, we could understand here, methyl group is present at one and three position and the total number of carbon are six and this is cyclo.
00:54
So it would be cyclohexane.
00:56
For six carbon, here is we should use hex.
01:01
So one, three, dimethyl because methyl group is present at one and three position of carbon.
01:11
Cyclo because it is cyclic group and hex because this the number of total number of carbons are six and ame because there is no double bond.
01:20
So this is the iupac name of this given compound.
01:24
Next is here numbering is one, two, three, four, five, six, seven.
01:33
Here at fourth carbon, ethyl group is present.
01:37
So four ethyl and total number of carbons are seven...