00:01
So, we have to predict here a structure of alkyene which is required so that we can get the particular products we have given here.
00:08
Okay, so the a part we have here, this is tert -butile alcohol, okay? tertiary -butyl alcohols.
00:20
So, let me draw the structure.
00:24
The structure will be, we have here a carbon atom which consists of three methyl growth.
00:34
Okay so now this is a tertiary carbon which is directly attached to oh group we need this product what kind of alken we should have okay so now if i consider a structure for alken like this let me draw this okay so there is double bond ch2 okay and so here hydration okay that is adding water molecule in presence of acid okay it is called acid hydration or you can also write the reagent as h positive this represent acid and water okay so this is acid hydration we have okay and we will follow here the markovnikov rule okay so this means that the on the double bonded carbon atom let me draw this structure first of all so now the markovnikov rule says that on the double bonded carbon atom the carbon with more hydrogen atom so on that we have to attach the oh h group the negative the positive part actually okay the positive part let me add the positive part positive part is here hydrogen okay and now on the carbon with less hydrogen atom we have to add negative part on that so this is the oh h group so this is the required structure okay then we have b part this time we have given isopropile iodide isopropile iodide okay so i see the super propyl iodide is carbon with two methyl groups.
03:21
So now how can i get this structure? so we have here this propene structure.
03:35
Okay, let me draw the propine structure.
03:40
Okay.
03:42
Now if i add h .i.
03:44
Here, hydrogen iodide and again i follow markovnikov rule, that is the negative part is to be added on the carbon.
03:50
With less hydrogen atom the positive part is to be aired on hydrogen with on the carbon with more hydrogen atom so the structure will be so now the hydrogen will be here right the carbon with more hydrogen atoms the positive part that is hydrogen this hydrogen right will be here and the negative part iodine will be here on this central carbon okay so this is the required structure, okay? so, we are following the markovnikov rule in the first two parts, okay? then we have c part.
04:35
This time we have isobutile bromide...