00:02
Okay, we're considering the radical bromination, monobromination, i believe, yes, of methyl cyclopentane, of isopropyl one methyl cyclopentane, or one isopropyl one methyl cyclopentane.
00:27
The same thing here, but with isopropal here as well.
00:34
Okay, and then 224 trimethymethylpentane.
00:46
Mono bromination radical bromination let's do i guess what i'll say is that let's do this in two steps let's assume that we've got a bromine radical right so the first step here is remember bromine selectively steals protons from tertiary carbons right that is we should expect that this would be the only proton abstracted by a radical bromine, and that the next step would include addition of bromine radical.
02:01
Okay.
02:07
And there we are.
02:08
That's the expected product.
02:12
So we can do the same thing over here.
02:14
We're basically just saying, find the tertiary proton if there is one, and if there is one, it'll be abstracted, and then leave mine a radical, and then that radical will, undergo a terminating step with another bromine radical, right? so do we have any tertiary hydrogens here? yeah, we do...